64(t)=64t-t^2

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Solution for 64(t)=64t-t^2 equation: 



64(t)=64t-t^2

We move all terms to the left:

64(t)-(64t-t^2)=0

We get rid of parentheses

t^2-64t+64t=0

We add all the numbers together, and all the variables

t^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{2}=0$

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